To calculate using sin, cos and tan, we need to know their trigonometric ratios (remember that the ratio of two values is a division of these values). Consider the right-angled triangle below. Consider the right-angled triangle below.
Finding Sin Cos Tan Values [Click Here for Previous Year Questions] Here, to find the sin, cos, tan values, Divide 0,1,2,3, and 4 by 4, then consider their positive roots of them. It can help get the sine ratios, which are, 0, ½, 1/√2, √3/2, and 1 for the angles 0°, 30°, 45°, 60° and 90°.
Letting the positive x -axis be the initial side of an angle, you can use the coordinates of the point where the terminal side intersects with the circle to determine the trig functions. The figure shows a circle with a radius of r that has an angle drawn in standard position. The equation of a circle is x2 + y2 = r2.
From the sin graph we can see that sinø = 0 when ø = 0 degrees, 180 degrees and 360 degrees. Note that the graph of tan has asymptotes (lines which the graph gets close to, but never crosses). These are the red lines (they aren't actually part of the graph). Also notice that the graphs of sin, cos and tan are periodic.
Evaluate inverse trig functions. The following are all angle measures, in degrees, whose sine is 1 . Which is the principal value of sin − 1 ( 1) ?
269. You can use a function like this to do the conversion: function toDegrees (angle) { return angle * (180 / Math.PI); } Note that functions like sin, cos, and so on do not return angles, they take angles as input. It seems to me that it would be more useful to you to have a function that converts a degree input to radians, like this:
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cos tan sin values